# Labaratory 0.5008 L 0.132 0.026 0.5309 ·

Labaratory
work

Venturi
meter

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Ignotas
Virginis   s16001586

Nick Burdon  ENG458

·
Introduction

The
main objectives of this experiment is to find the coefficient of discharge from
experimental data using Venturi meter. Find relationship between flow area,
pressure and velocity.

With this laboratory work we get good understanding
of Bernoulli’s equation and its applications in flow analysis. In experiment,
we recorded fluid levels of 11 tubes.

·      Materials

Venturi meter with fluid.

·      Method

Check the schematic plate
on the back on the Venturi meter. It shows the cross- sectional areas and
distances to each point in the Venturi meter. Turn the pump on and adjust the
flow rate to a constant level using the valve on the tub. To adjust the
flowrate for the rest of the lab, use the valve located on the Venturi meter.
This will avoid introducing air into the system. ?Set the discharge as
high as possible (water in all piezometers must be readable on the each of
their scales) making sure there are no air bubbles in the piezometer tubes.
Record the water heights in all of the piezometers in Table 1. ?Find the flow rate using the Mag Meter. Record the results in
Table 2. ?Readjust both valves so that a difference in water heights in
cross-sections A and D is 3?4 of what it was in step 3. Record all levels and
find the discharge. ?Repeat step 5 two more times with the
difference in water levels between 1?2 and 1?4 of what it was in step 3. ?For a final check, shut off the flow into the Venturi meter and
make sure all of the water levels are the same. ?

·      Data

Tubes

Height
(m)

Diameter
(m)

Area (m2)

A

0.154

0.026

0.5309

B

0.139

0.0232

0.4227

C

0.089

0.0184

0.2659

D

0.023

0.016

0.201

E

0.032

0.0168

0.2217

F

0.074

0.01847

0.268

G

0.99

0.02016

0.3188

H

0.112

0.02184

0.375

J

0.121

0.02353

0.435

K

0.128

0.02524

0.5008

L

0.132

0.026

0.5309

·      Calculations

Formulas:

1)

2)
Va=

3)Cvb=

Mcalc=

Mreal= = 0.325

4) Qb=

B.

1)    ( Pa – Pb ) = 1000 * 9.81 * ( ( 154 –
139 ) x10-3 ) =147.17 N/m2

2)    Vb = = 0.897 m/s2

3)    Cvb =  = 1.167

4)    Qb = 0.0004227*0.897 = 379.16×10-6

C.

1)    ( Pa – Pc ) = 1000 * 9.81 * ( ( 154 –
89 ) x10-3 ) =637.65 N/m2

2)    Vc = = 1.305 m/s2

3)    Cvc =  = 1.068

4)    Qc = 0.0002659*1.305 = 347×10-6

D.

1)    ( Pa – Pd ) = 1000 * 9.81 * ( ( 154 –
23 ) x10-3 ) =1285.11 N/m2

2)    Vd = = 1.732 m/s2

3)    Cvd =  = 1.072

4)    Qd = 0.0002011*1.732 = 347×10-6

E.

1)    ( Pa – Pe ) = 1000 * 9.81 * ( ( 154 –
32 ) x10-3 ) =1196.82 N/m2

2)    Ve = = 1.703 m/s2

3)    Cve =  = 1.162

4)    Qe = 0.0002217*1.703 = 377.56×10-6

F.

1)    ( Pa – Pf ) = 1000 * 9.81 * ( ( 154 –
74 ) x10-3 ) = 784.8 N/m2

2)    Vf = = 1.451 m/s2

3)    Cvf =  = 1.917

4)    Qf = 0.000268*1.451 = 388.87×10-6

G.

1)    ( Pa – Pg ) = 1000 * 9.81 * ( ( 154 –
99 ) x10-3 ) = 539.55 N/m2

2)    Vg = = 1.3 m/s2

3)    Cvg =  = 1.275

4)    Qg = 0.0003188*1.3 = 414.12×10-6

H.

1)    ( Pa – Ph ) = 1000 * 9.81 * ( ( 154 –
112 ) x10-3 ) = 417.02 N/m2

2)    Vh = = 1.281 m/s2

3)    Cvh =  = 1.479

4)    Qh = 0.000375*1.281 = 480.4×10-6

J.

1)    ( Pa – Pj ) = 1000 * 9.81 * ( ( 154 – 121
) x10-3 ) = 323.73 N/m2

2)    Vj = = 1.402 m/s2

3)    Cvj =  = 1.876

4)    Qj = 0.000435*1.402 = 609.87×10-6

K.

1)    ( Pa – Pk ) = 1000 * 9.81 * ( ( 154 – 128
) x10-3 ) = 255.1 N/m2

2)    Vk = = 2.135 m/s2

3)    Cvk =  = 3.292

4)    Qk = 0.0005008*2.135 = 1069.21×10-6

·      Results and discussion

What
we get from results and data, graphs . whats good whats bad

·      Conclusion